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Infinity Hotel

Infinity Hotel has an infinite number of rooms numbered 0, 1, … and serves an infinite number of guests with personal identifiers 0, 1, …. All guests want a room of their own.

A finite subset of the guests S are VIPs that always stay in a room that is specifically prepared for them. This assignment of VIPs to rooms is given by an injection f.

You are given the following tasks:

  1. Show that the hotel can serve the VIPs and all other guests. That is, show that there is an injection g from all the guests to the room numbers that respects f on S.

  2. Show that the hotel can serve the VIPs and all other guests and also fill all its rooms. That is, show that there is a bijection h between all the guests and the room numbers that respects f on S.

Thanks to Simon Wimmer for stating the problem. Thanks to Armaël Guéneau and Kevin Kappelmann for translating.

Resources

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Definitions File

theory Defs
  imports "HOL-Library.Infinite_Set"
begin

end

Template File

theory Submission
  imports Defs
begin

text ‹Task 1 - 1/5 points›
theorem injective_embedding:
  fixes f :: "nat ⇒ nat"
    and S :: "nat set"
  assumes "inj_on f S" and "finite S"
  shows "∃g. inj_on g ℕ ∧ (∀x ∈ S. g x = f x)"
sorry

text ‹Task 2 - 4/5 points›
theorem bijective_embedding:
  fixes f :: "nat ⇒ nat"
    and S :: "nat set"
  assumes "inj_on f S" and "finite S"
  shows "∃h. bij_betw h ℕ ℕ ∧ (∀x ∈ S. h x = f x)"
  sorry

end

Check File

theory Check
  imports Submission
begin

theorem injective_embedding:
  fixes f :: "nat ⇒ nat"
    and S :: "nat set"
  assumes "inj_on f S" and "finite S"
  shows "∃g. inj_on g ℕ ∧ (∀x ∈ S. g x = f x)"
  using assms by (rule Submission.injective_embedding)

theorem bijective_embedding:
  fixes f :: "nat ⇒ nat"
    and S :: "nat set"
  assumes "inj_on f S" and "finite S"
  shows "∃h. bij_betw h ℕ ℕ ∧ (∀x ∈ S. h x = f x)"
  using assms by (rule Submission.bijective_embedding)

end
Download Files

Definitions File

-- Lean version: 3.4.2
-- Mathlib version: 2019-09-11

import data.finset
open function

-- Coercion from finite sets to sets
@[simp] protected def finset.coe_set {α : Type*} : has_coe (finset α) (set α) := ⟨finset.to_set⟩

-- The goals used in submission
notation `GOAL_INJECTIVE` :=
∀ {S : finset ℕ} (f : S ↪ ℕ), ∃ (h : ℕ ↪ ℕ), restrict h S = f
notation `GOAL_BIJECTIVE` :=
∀ {S : finset ℕ} (f : S ↪ ℕ), ∃ (h : ℕ → ℕ), bijective h ∧ restrict h S = f

Template File

import .defs

open function
local attribute [instance] finset.coe_set
local infixr `|` :100 := restrict -- write f|S for restrict f S

-- 1/5 points
lemma submission_injective :
  ∀ {S : finset ℕ} (f : S ↪ ℕ), ∃ (h : ℕ ↪ ℕ), h|S = f := sorry

-- 4/5 points
theorem submission_bijective :
  ∀ {S : finset ℕ} (f : S ↪ ℕ), ∃ (h : ℕ → ℕ), bijective h ∧ h|S = f := sorry

Check File

import .defs
import .submission

open function
local attribute [instance] finset.coe_set

theorem goal_injective :
  ∀ {S : finset ℕ} (f : S ↪ ℕ), ∃ (h : ℕ ↪ ℕ), restrict h S = f :=
@submission_injective

theorem goal_bijective :
  ∀ {S : finset ℕ} (f : S ↪ ℕ), ∃ (h : ℕ → ℕ), bijective h ∧ restrict h S = f :=
@submission_bijective
Download Files

Definitions File

Require Export ConstructiveEpsilon.
Require Export List Lia.
Export ListNotations.

Definition inj {A B : Type} (f : A -> B) :=
  forall a a', f a = f a' -> a = a'.

Definition inj_on {A B : Type} (P : A -> Prop) (f : A -> B) :=
  forall a a', P a -> P a' -> f a = f a' -> a = a'.

Definition surjective {A B : Type} (f : A -> B) :=
  forall b, exists a, f a = b.

Definition bij {A B : Type} (f : A -> B) :=
  exists g, (forall a, g (f a) = a) /\ (forall b, f (g b) = b).

Coercion is_true (b : bool) := b = true.

Template File

Require Import Defs.

Section InfinityHotel.

Variable VIP : nat -> bool.
Variable VIP_bound : nat.
Hypothesis VIP_bounded : forall x, VIP x -> x < VIP_bound.

Variable f : nat -> nat.
Variable f_inj : inj_on VIP f.

(* 1/5 points *)
Theorem task1 : exists g, inj g /\ forall x, VIP x -> g x = f x.
Admitted.

(* This will be useful *)
Check constructive_indefinite_ground_description_nat_Acc.

Lemma inj_surj_bij (g : nat -> nat) : inj g -> surjective g -> bij g.
Admitted.

(* 4/5 points *)
Theorem task2 : exists g, bij g /\ forall x, VIP x -> g x = f x.
Admitted.

End InfinityHotel.

Terms and Conditions